更多"设z=x2y+y2,则dz=______."的相关试题:
[简答题]设方程ez=1+xz+x2+y2确定隐函数z=z(x,y),求dz与z"xy。
[简答题]设方程ez=y+xz+x2+y2确定隐函数z=z(x,y),求dz与z"xy.
[简答题]设z=z(x,y)由方程z3y-xz-1=0确定,求dz.
[简答题]设z=z(x,y)由方程e2-xy+y+z=0确定,求dz.
[简答题]设z=z(x,y)由方程ez-xy2+x+z=0确定,求dz.
[简答题]设z=z(x,y)由方程ez-xy2+sin(y+z)=0确定,求dz,
[简答题]设z=z(x,y)由ez-xyz=1所确定,求全微分dz.
[简答题]设z=z(x,y)由方程e2-x2+y2+x+z=0确定,求dz.
[填空题]设z=esinxy,则dz=______.
[简答题]设z=sin(xy2)+ex2y,求dz.
[简答题]设z=z(x,y)是由方程x2+2y2+xy+z2=0所确定的隐函数,求全微分dz.