更多"[判断题]The Smoot-Hawley Act raised ta"的相关试题:
[判断题]. (判断题,)The Smoot-Hawley Act raised tariff barriers in the hope of protecting jobs and diverting consumer demand away from foreign products.
A.正确
B.错误
[判断题]. (判断题,)Tariff barriers lower the costs of exporting products to a country.
A.正确
B.错误
[判断题]
Once barriers to trade and investment are removed, companies can treat a group of integrated countries like the EU as a single market and produce standardized products for it.
A.正确
B.错误
[判断题]
The Foreign Corrupt Practices Act originally allowed "facilitating payments" to secure contracts that would not otherwise be secured.()
A.正确
B.错误
[判断题]
The Foreign Corrupt Practices Act outlawed the paying of bribes to foreign government officials to gain business.
A.正确
B.错误
[判断题]
The Single European Act committed EU countries to adopting a common currency by January 1., 19.99..()
A.正确
B.错误
[单选题]以下程序的输出结果是？
int i;
for(i='a';i<'f';i++,i++)
{
Console.Write((char)(i - 'a' + 'A'));
}
A.ACE
B.BDF
C.ABD
D.CDE
[判断题]
Governments do not always act in the national interest when they intervene in the economy; politically important interest groups often influence them.
A.正确
B.错误
[单选题]下列代码输出结果是()
int i=10;
while(i>0){
i=i+1;
if(i==10){
break;
}
}
A.while循环执行10次
B.死循环
C.循环一次都不执行
D.循环执行一次
[判断题]三相对称负载星形联接的电路中，I线与I相之间的关系是I线=I相。
A.正确
B.错误
[判断题]低温可以使ACT明显缩短。( )
A.正确
B.错误
[单选题]有以下程序
Main()
{ char k; int i;
For(i=1;i<3;i++)
{ scanf("%c",&k);
Switch(k)
{ case '0': printf("another\n");
Case '1': printf("number\n");
}
}
}
程序运行时,从键盘输入:01↙,程序执行后的输出结果是()。
A.another
Number
B.another
Number
Another
C.another
Number
Number
D.number
Number
[单选题]有以下程序
Main()
{ int i;
For(i=0;i<3;i++)
Switch(i)
{ case 1: printf("%d",i);
Case 2: printf("%d",i);
Default: printf("%d",i);
}
}
执行后输出的结果是()。
A.011122
B.012
C.012020
D.120
[单选题]有以下程序:
Main()
{ int i;
For(i=0;i<3;i++)
Switch(i)
{
Case 0:printf("%d",i);
Case 2:printf("%d",i);
Default:printf("%d",i);
}
}
程序运行后的输出结果是()。
A.022111
B.021021
C.000122
D.012
[判断题]直流串联电路的总电流等于各支路电流之和,即I=I1+I2+I3+…+In。
A.正确
B.错误
[单选题]有以下程序
Main()
{ int i;
For(i=1;i<=40;i++)
{ if(i++%5==0)
If(++i%8==0) printf ("%d",i);
}
Printf("\n");
}
执行后的输出结果是()。
A.5
B.24
C.32
D.40
[单选题]有以下程序
Main()
{ int i, j;
For(i=1;i<4;i++)
{ for(j=i;j<4;j++)
Printf("%d*%d=%d ",i,j,i*j);
Printf("\n");
}
}
程序运行后的输出结果是()。
A.1*1=1 1*2=2 1*3=3
2*1=2 2*2=4
3*1=3
B.1*1=1 1*2=2 1*3=3
2*2=4 2*3=6
3*3=9
C.1*1=1
1*2=2 2*2=4
1*3=3 2*3=6 3*3=9
D.1*1=1
2*1=2 2*2=4
3*1=3 3*2=6 3*3=9
