已知C源程序如下:
/*Input today’s date,output tomorrow’s date * /
/* version 2 * /
#include<stdio. h>
struct ydate
int day; int month; int year;;
int leap(struct ydate d)
if((d. year%4==0&&d. year%100 ! =0)||(d. year%400==0))
return 1;
else
return 0;
int numdays(struct ydate d)
int day;
static int daytab[]=
31,28,31,30,31,30,3l,31,30,31,30,31;
if(1eap(d)&&d. month==2)
day=29;
else
day=daytabEd. month-1];
return day;
int main(void)
struct ydate today,tomorrow;printf("format of date is:year,month,day输入的年、月、日之间应用逗号隔开/n);
printf(" today is:");
scanf(“%d,%d.%",&today.year,&today.month,&today.day);
while(0>=today. year
|| today. year>65535||0>=today. month||today. month>12)||
0>=today. day||today. day>numdays(today))
printf("input date error!reenter the day!/n");<
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