更多"有下列的程序: #include<cstring.h> #incl"的相关试题:
[单项选择]有如下程序
#include
#include
using namespace std;
class MyClass{
public:
MyClass( ){cout<<′A′;}
MyClass(char c){cout<<′c′;}
MyClass( ){cout<<′B′;}
}
int main( ){
MyClass pl,*p2;
p2=new MyClass(′X′);
delete p2;
retum 0;
}
执行这个程序屏幕上将显示输出【 】
A. ABX
B. ABXB
C. AXB
[单项选择]有如下程序
#include
#include
using namespace std;
int main( )
cout<A. setprecision(3)
B. fixed
C. setfill(′*′)
D. setw(8)
[单项选择]有如下的程序:
#include
#include
usingnamespacestd;
classMyString
{public:
MyString(constchar*s);
MyString(){delete[]data;}
protected:
unsignedlem
char*data;};
MyStrin9::MyString(constchar*s)
{len=strlen(s);
data=newchar[len+1];
strcpy(data,s);}
intmain()
{MyStringa("C++Programing");
MyStringb(a);
return0;}
在运行上面的程序时出错,出错的原因是( )。
A. 构造函数的实参不允许是本类的对象
B. 没有定义实现深层复制的复制构造函数
C. 构造对象a时实参与形参类型不符
D. 系统不能生成默认的复制构造函数
[简答题]有如下程序
#include
#include
using namespace std;
class MyClass{
public:
MyClass( ){cout<<’A”;}
MyClass(char c {cout<A. A.ABX
B.ABXB
C.AXB
D.AXBB
[填空题]
以下程序运行后的输出结果是()。
#include
#include
#include
main( )
{ char *p;int i;
p=(char*)malloc(sizeof(char)*20);
strcpy(p,"welcome");
for(i=6;i>=0;i--) putchar(*(p+i));
printf("/n"); free(p);
}
[单项选择]有如下程序
#include <iostream>
#include <iomanip>
using namespace std;
int main( )
cout<<setprecision(3)<<fixed<<setfill(’*’)<<setw(8);
cout<<12.345<<__________<<34.567;
return 0;
若程序的输出是:
**12.345**34.567
则程序中下划线处遗漏的操作符是( )。
A. setprecision(3)
B. fixed
C. setfill(’*’)
D. setw(8)
[单项选择]有以下程序
#include <iostream>
#include <string>
using namespace std;
class base
private:
char baseName[10];
public:
base( )
strcpy(baseName,"Base");
virtual char *myName( )
return baseName;
char *className( )
Return baseName;
;
class Derived: public base
private:
char derivedName[10];
public:
Derived( )
strcpy(derivedName,"Derived" );
char *myName( )
return derivedName;
char *className( )
return derivedName;
;
void showPtr(base &p)
cout<<p.myName( )<<" "<<p.className( );
int main( )
base bb;
Derived dd;
showPtr(dd);
return 0;
运行后的输出结果为
A. Derived Base
B. Base Base
C. Derived Derived
D. Base Derived
[单项选择]下面程序的输出结果是( )。
#include
#include
voidmain()
{
charp1[10],p2[10];
strcpy(p1,"abc");
strcpy(p2,"ABC");
charstr[50]="xyz":
strcpy(str+2,strcat(p1,p2));
cout< }
A. xyzabcABC
B. zabcABC
C. xyabcABC
D. yzabcABC
[单项选择]有以下程序
#include <iostream>
#include <string>
using namespace std;
class base
private:
char baseName[10];
public:
base ( )
strcpy(baseName,"Base");
virtual char *myName( )
return baseName;
char *className( )
return baseName;
;
class Derived : public base
private:
char derivedName[10];
public:
Derived( )
strcpy(derivedName,"Derived");
char *myName( )
return derivedName;
char *className( )
return derivedName;
;
void showPtr(base &p)
cout<<p.myName ( ) <<" "<<p.className ( );
int main ( )
base bb;
Derived dd;
showPtr(dd);
return 0;
运行后的输出结果为
A. Derived Base
B. Base Base
C. Derived Derived
D. Base Derived
[单项选择]有如下程序:
#include<cstring>
#include<iostream>
using namespace std;
class MyString
public:
MyString(const char * s);
~MyString( )delete[ ]data;
protected:
unsigned len;
char * data;
;
MyString::MyString(const char * s)
len=strlen(s);
data=new char[1en+1];
strcpy(data,s);
int main( )
MyString a("C++Progreanfing");
MyString b(
A. ;
B. 没有定义实现深层复制(深复制)的复制构造函数
C. 构造对象a时实参与形参类型不符
D. 系统不能生成缺失的复制构造函数