题目详情
当前位置:首页 > 职业培训考试
题目详情:
发布时间:2023-12-15 20:08:41

[单项选择]下列程序的运行结果是
#include<iostream.h>
class Location
private:
int X.Y;
public:
void init(int=0,int=0);
void valueX(int val)X=val;
int valueX( ) return X;
void valueY(int val)Y=val;
int valueY( )return Y;;
void Location::init(int init X,int init Y)
X=initX;
Y=initY;
void main( )
Location A,B;
A.init( );
A.valueX(5);
cout<<A.valueX( )<<endl<<A.valueY( )<<endl;
B.init(6,2);
B.valueY(4);
cout<<B.valueX( )<<endl<<B.valueY( )<<endl;
A. 5
B. 0
C. 5
D. 0

更多"下列程序的运行结果是 #include<iostream.h>"的相关试题:

[单项选择]下列程序的运行结果是 #include<iostream.h> class Location{ private: int X.Y; public: void init(int=0,int=0); void valueX(int val){X=val;} int valueX( ){ return X;} void valueY(int val){Y=val;} int valueY( ){return Y;}}; void Location::init(int init X,int init Y) { X=initX; Y=initY;} void main( ) { Location A,B; A.init( ); A.valueX(5); cout<<A.valueX( )<<endl<<A.valueY( )<<endl; B.init(6,2); B.valueY(4); cout<<B.valueX( )<<endl<<B.valueY( )<<endl;}
A. 5 0 6 4
B. 0 0 6 4
C. 5 0 6 2
D. 0 0 6 2
[单项选择]下列程序的运行结果是
#inClUde<iostream.h>
class Location
private:
int X,Y;
pubhc:
void init(int=0,int=0) ;
void valueX(int val) X=val;
int valueX( ) retum X;
void valueY(int val) Y=val;
int valueY( ) retum Y;;
void Location: :init(int initX,int initY)
X=initX;
Y=initY;
Void main( )
Location A,B;
A. init( ) ;
A. valueX(5) ;
cout < < A. valueX( ) < < endl < < A. valueY( ) < < endl;
B. init(6,2) ;
B. valueY(4) ;
cout < < B. valueX( ) < < endl < < B. valueY( ) < < endl;
A. 5
B. 0
C. 5
D. 0
[单项选择]下面程序的运行结果是 #include<iostream.h> class base{ protected: int a; public: base( ) {cout < < "0";} }; class base l: virtual base{ public: base l ( ) {cout < <"1";} }; class base 2: virtual base{ public: base2 ( ) {cout < <"2";} }; class derived: public base 1, public base2{ public: derived( ) {cout < < "3";} }; void main( ) { derive obj; cout < < endl; } A) 0123 B) 3120 C) 0312 D) 3012
[单项选择]下面程序的运行结果是
#include<iostream.h>
class base
protected:
int a;
public:
base( )cout <<"0";

class basel:virtual base
public:
basel ( ) cout <<"1";

class base2:virtual base
public:
base2( )cout <<"2";

class derived:public basel,public base2
public:
derived( )cout <<"3";

void main( )

derived obj;
cout <<end1;

A. 0123
B. 3120
C. 0312
D. 3012
[单项选择]下列程序的运行结果是
#include<iostream.h>
class A

int a;
public:
A( )a=0;
A(int aa)

a=aa;
cout<<a++;


void main( )

A x,y(2),z(3);
cout<<end1;

A. 00
B. 23
C. 34
D. 25
[单项选择]下列程序的输出结果是
#include
class Myclass
public:Myclass(int i=0,intj=0)
x=i;
y=j;

void show( ) cout < < "x=" < < x < < " " < "y=" < < y < < end1;
void show( )const cout < < "x=" < < " " < < "y=’ < < y < < end1;
privated:
int x; int y;

void main( )
Myclass my1(3,4);
const my2(7,8);
my1.show( );my2.show( );
A. x=4,y=3;x=7,y=8
B. x=3,y=4;x=7,y=8
C. x=7,y=8;x=4,y=3
D. x=8,y=7;x=7,y=8
[单项选择]分析下面程序,该程序的运行结果是( )。
#include<iostream.h>
class cmm

public:
static int m;
cmm( )

m++;

cmm(int n)

m=n;

static void testm( )

m++;

;
int cmm :: m=0;
void main( )

cmm A;
cmm B(3);
A. testm();
B. m=3
C. m=4
D. m=5
E. m=6
[单项选择]下面程序的运行结果是 #include<iostream.h> class base{ protected: int a; public: base( ){cout <<"0";} }; class basel:virtual base{ public: basel ( ) {cout <<"1";} }; class base2:virtual base{ public: base2( ){cout <<"2";} }; class derived:public basel,public base2{ public: derived( ){cout <<"3";} }; void main( ) { derived obj; cout <<end1; }
A. 0123
B. 3120
C. 0312
D. 3012

我来回答:

购买搜题卡查看答案
[会员特权] 开通VIP, 查看 全部题目答案
[会员特权] 享免全部广告特权
推荐91天
¥36.8
¥80元
31天
¥20.8
¥40元
365天
¥88.8
¥188元
请选择支付方式
  • 微信支付
  • 支付宝支付
点击支付即表示同意并接受了《购买须知》
立即支付 系统将自动为您注册账号
请使用微信扫码支付

订单号:

截图扫码使用小程序[完全免费查看答案]
请不要关闭本页面,支付完成后请点击【支付完成】按钮
恭喜您,购买搜题卡成功
重要提示:请拍照或截图保存账号密码!
我要搜题网官网:https://www.woyaosouti.com
我已记住账号密码