更多"有以下程序: #include <iostream> #inclu"的相关试题:
[单项选择]有以下程序:
#include <iostream>
#include <cmath>
using namespace std;
class Distance;
class point
public:
friend class Distance;
Point(int a,int B)
x=a;
Y=b;
void Print( )
cout<<"X= "<<X<<end1;
cout<<"Y= "<<Y<<end1;
private:
float X,Y;
;
class Distance
public:
float Dis(Point &p,Point &q);
;
float Distance :: Dis(Point &p,Point &q)
float result;
result=sqrt((p.X-q.X)*(p.X-q.X)+(p.Y-q.Y)*(p.Y-q.Y));
cout<<result<<end1;
retUrn result;
int main( )
Point p(10,10),q(10,30);
Distance d;
d.Dis(p,q);
return 0;
运行后的输出结果是( )。
A. 10
B. 30
C. 0
D. 20
[单项选择]有以下程序 #include <iostream> #include <string> using namespace std; class base { private: char baseName[10]; public: base ( ) { strcpy(baseName,"Base"); } virtual char *myName( ) { return baseName; } char *className( ) { return baseName; } }; class Derived : public base { private: char derivedName[10]; public: Derived( ) { strcpy(derivedName,"Derived"); } char *myName( ) { return derivedName; } char *className( ) { return derivedName; } }; void showPtr(base &p) { cout<<p.myName ( ) <<" "<<p.className ( ); } int main ( ) { base bb; Derived dd; showPtr(dd); return 0; } 运行后的输出结果为
A. Derived Base
B. Base Base
C. Derived Derived
D. Base Derived
[单项选择]下面程序中对一维坐标点类Point进行运算符重载
#include <iostream>
using namespace std;
class Point f
public:
Point(int val) x=val;
Point& operator++( ) x++; return *this;
Point operator++(int) Point old=*this;++(*this);return old;
int GetX( ) const return x;
private:
int x;
;
int main( )
Point a(10);
cout<<(++a).GetX( );
cout<<a++.GetX( );
return 0;
编译和运行情况是( )。
A. 运行时输出1011
B. 运行时输出1111
C. 运行时输出1112
D. 编译有错
[单项选择]应在下面程序下划线中填写的正确的语句是( )。
#include <iostream>
using namespace std;
class A
public:
void test( )cout<< "this is A!";
;
class B:public A
void test( )
______ //显示调用基类函数test( )
cout<< "this is B!";
;
void main( )
A. A) :test()
B. C) :test()
[单项选择]下列程序的输出结果为2,横线处应添加语句( )。
#include<iostream>
using namespace std;
public:
______void fun( )cout<<1;
;
class TestClass2:public TestClass1
public:void fun( )cout<<2;)
;
int main( )
TestClass1 *p=new TestClass2;
p->fun( );
delete p;
Teturn 0;
A. public
B. private
C. virtual
D. protected
[填空题]下面程序的输出结果是〈u〉 【9】〈/u〉。
#include 〈iostream〉
using namespace std;
void f(int x)
{
if(x)
{
cout.put(’0’+x%10);
f(x/10);
}
}
int main( )
{
f(11001);
return 0;
}
[单项选择]有如下程序:
#include<iostream>
#include<iomanip>
using namespace std;_
int main( )
Cout<<setw(10) <<setfill('x')<<setprecision(8) <<left;
Cout<<12.3456793<<_______<<98765;
return 0;
若程厚的输出是12.345679x98765xxxxx,则划线处缺失的部分是
[填空题]有以下程序:
#include <iostream>
#include <fstream>
using namespace std;
int main( )
{
fstream file;
file.open("abc.txt", ios_base::in);
if (! file )
{
cout<<"Can not open abc.txt"<<end1;
abort( );
}
char ch;
int i = 0;
while ( ! file.eof( ) )
{
file.get(ch);
i++;
}
cout<<"Characters : "<<i<<end1;
file.close( );
return 0;
}
程序实现的功能是 【15】 。
[单项选择]有以下程序:
#include<iostream>
#include<string>
using namespace std;
int main( )
char arr[2][4];
strcpy(arr[0],"you");
strcpy(arr[1],"me");
arr[0][3]='&';
cout<<arr[0]<<end1;
return 0;
执行后的输出结果是( )。
A. you&me
B. you
C. me
D. err
[单项选择]有以下程序 #include<iostream> #include<string> using namespace std; class base { private: charbaseName[10]; public: base( ) { strcpy(baseName,"Base"); } virtual char*myName( ) return baseName; } char *className( ) { return baseName; } }; class Derived: public base { private: char derivedName[10]; public: Derived( ) { strcpy(derivedName,"Derived"); } char *myName( ) { return derivedName; } char *className( ) { return derivedName; } }; void showPtr(base &p) { cout<<p.myName0<<" "<<p.className( ); } int main( ) { base bb; Derived dd; showPtr(dD) ; retum 0; } 动行后的输出结果为
A. Derived Base
B. Base Base
C. Derived Derived
D. Base Derived
[单项选择]有以下程序: #include <iostream> #include <fstream> using namespace std; int main ( ) { ofstream ofile; char ch; ofile.open ("abc.txt"); cin>>ch; while (ch!=’#’ ) { cin>>ch; ofile.put(ch); } ofile.close( ); return 0; } 当从键盘终端连续输入的字符为a、b、c和#时,文件abc.txt中的内容为( )。
A. 程序编译时出错
B. abc#
C. abc
D. #
[单项选择]有以下程序: #include<iostream> #include<math> using namespace std; class point { private: double x; double y; public: point(double a,double B) { x=a; y=b; } friend double distance (point a,point B) ; }; double distance (point a,point B) { return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y)); } int main( ) { point p1(1,2); point p2(5,2); cout<<distance(p1,p2)<<end1; return 0; } 程序运行后的输出结果是
A. 1
B. 5
C. 4
D. 6