更多"Interviewing Skills, by Hazel Conwa"的相关试题:
[单项选择]
Interviewing Skills, by Hazel Conway
The aim of interviewing is to fill vacancies with suitable people, and Hazel Conway points out that if all interviewers were skilled, far fewer people would be given jobs they cannot do, and then leave soon afterwards. It is generally recognised that the cost of recruiting a replacement can equal an annual salary, but it is a weakness of Conway’s book that it does not deal with the costs that ineffective interviewing techniques can lead to.
Conway claims that the traditional ’question and answer’ interview between two people depends too much on whether the interviewer likes the candidate, and not enough on whether he or she has the skills necessary for the job.
Interviewing Skills usefully covers everything an employer needs to know about preparing for and holding interviews, such as researching the applicant’s work experience. Surprisingly, Conway differs from many writers in considering that applicants’ persona
[单项选择]已知下列函数定义:
fun(int%,int c,int n,int data)
int k;
for(k=0;k<m*n;k++)
*b=data;
b++;
则调用此函数的正确写法是(假设变量a的说明为int a[50])()。
A. fun(*a,4,5,1);
B. fun(&a,4,5,1);
C. fun((int*)a,4,5,1);
D. fun(a,4,5,1);
[单项选择]有以下程序:
int a=4;
int f(int n)
int t=0;static int a=5;
if(n%2) int a=6;t+=a++;
elseint a;7;t+=a++;
return t+a++;
main( )
int s=a,i=0;
for(;i<2;i++)s+=f(i);
printf("%d/n",s);
程序运行后的输出结果是()。
A. 24
B. 28
C. 32
D. 36
[填空题]下列程序的输出结果是 【11】 。
int t(int x,int y,int cp,int dp)
{ cp=x* x+y*y;
dp=x*x-y*y;
}
main( )
{ int a=4,b=3,c=5,d=6;
t(a,b,c,d);
printf("%d%d/n",c,d);
}
[填空题]下列程序的输出结果是 【11】 。
int t(int x,int y,int cp,int dp)
cp=x* x+y*y;
dp=x*x-y*y;
main( )
int a=4,b=3,c=5,d=6;
t(a,b,c,d);
printf("%d%d/n",c,d);
[填空题]下列程序的输出结果是 【11】 。
int t(int x,int y,int cp,int dp)
cp=x*x+y*y;
dp=x*x-y*y;
main( )
int a=4,b=3,c=5,d=6;
t(a,b,c,D) ;
print f("%d%d/n",c,D) ;
[单项选择]
有以下程序:
int a=2;
int f(int n)
{static int a=3;
int t=0;
if(n%2){static int a=4;t+=a++;
}
else
{
static int a=5; t+=a++;
}
return t+a++;
}
main( )
{ int s=a,i;
for(i=0;i<3;i++) s+=f(i);
printf("%d/n",s);
}
程序运行后的输出结果是()。
A. 26
B. 28
C. 29
D. 24
[简答题]#include<stdio.h>
int trans(int m,int n)
int i;
if(m>n)
i=m%n;trans(m,n);
else i=m:
if(i<10)printf("%d/n",i):
else printf("%c",’A’+i-10):
main( )
int i;
printf("The output is:/n");
printf("n%d/n",-23);
trans(21,3);
printf("n%d/n",123);
trans(123,16);
[填空题]
有如下的函数定义:
int Xfun(int*a,int n)
int X*a;
for(int*pa=a+1;pa if(*pa>x)x=*pa;
retum x;
若在执行了语句:
int x[5]=(23,46,78,55,16);
后,通过表达式Xfun(x,5)调用该函数,则得到的返回值为______。
[填空题]下列程序的输出结果是______。
int t(int x,int y,int cp,int dp)
cp=x% y+y*y;
dp=x+x-y*y;
main( )
im a=4,b=3,c=9,d=8;
t(a,b,c,d);
printf("%d%d/n",c,d);