有如下程序： #include＜iostream＞ using n-我要搜题网

[单选题]业主项目部根据《国网公司输变电工程设计施工监理承包商资信及调试单位资格管理办法》（国网〔基建/3〕 116-2015）相关规定，每（）按照设计质量评价表（见附录中PDW39）的评价内容和评价标准，配合建设管理单位完成对设计单位的设计质量（工程指标）评价，并及时将评价结果上报建设管理单位，由项目法人或建设管理单位负责综合指标评价及资信评价
A.半年
B.一年
C.两年
D.三年

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[多选题]高层民用建筑中庭连通面积叠加超过一个防火分区最大允许建筑面积时,应采取( )等措施。
A.房间与中庭回廊相通的门.窗,应设火灾时能自行关闭的甲级防火门.窗
B.与中庭相通的过厅.通道等,应设乙级防火门或耐火极限大于3H的防火卷帘分隔
C.中庭每层回廊应设自动喷水灭火系统
D.中庭每层回廊应设火灾自动报警系统

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[多选题] 关于防误装置的解锁规定,包含下列哪些方面()
A. 解锁申请
B. 解锁批准
C. 解锁监护
D. 解锁使用记录

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[判断题]虽然门禁车站级系统与中央服务器通讯中断不影响门禁就地设备的使用，但会导致操作门禁就地设备的数据无法上传的中央服务器
A.正确
B.错误

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[多选题]《消防法》规定火灾现场总指挥根据扑救火灾的需要，有权决定调动什么有关单位协助灭火救援？
A.供水
B.供电
C.供气
D.通信
E.医疗救护
F.交通运输

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[单选题]攂电气集中，列车开始继电器电路中，当进路内方第一道岔区段解锁后，( )复原，断开LKJ第二条自闭电路。
A.KJ
B.方向继电器
C.FKJ
D.AJ

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[判断题]使用吊车撤杆时，应先检查有无卡盘或障碍物并试拔。
A.正确
B.错误

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[判断题]冬季职工作业特点：冷、长、滑、凝、笨、畏、忙。
A.正确
B.错误

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[判断题]轮对压装时，如果配合面粗糙度过高，会造成压装力过低。
A.正确
B.错误

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[判断题]锤头磨碎严重可造成复合式破碎机电流过高。
A.正确
B.错误

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[不定项选择题]男性，70岁，主诉上腹部疼痛3个月并逐渐加重来诊，近来疼痛以夜间为重，坐起前倾位疼痛可以减轻，食欲不振，伴腹泻，脂肪餐后腹泻加重。两个月来体重减轻7.5千克，曾行胃镜检查诊为“慢性重度萎缩性胃炎”，上消化道钡餐检查无阳性体征，化验发现血糖增高。能尽早提供诊断线索的首选检查方法是
A.B超
B.十二指肠低张造影
C.选择性腹腔动脉造影
D.CT
E.腹部平片

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[单项选择]风险对房地产投资决策的影响，主要体现在如下( )方面。
A. 根据项目风险大小确定相应的投资收益水平
B. 根据风险管理的能力选择投资方向
C. 根据风险周期变化特点把握投资时机
D. 以上全部正确

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[判断题]铁路货车按其用途分为通用货车、专用货车、特种货车三类。( )
A.正确
B.错误

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[多项选择]动笔撰写公文前要选好文种，选择文种的依据有( )。
A. 政策法规依据
B. 工作关系依据
C. 职权范围依据
D. 行文目的依据

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[单项选择]

The following questions present a sentence, part of which or all of which is underlined. Beneath the sentence, you will find five ways of phrasing the underlined part. The first of these repeats the original; the other four are different. If you think the original is best, choose the first answer; otherwise choose one of the others.
These questions test correctness and effectiveness of expression. In choosing your answer, follow the requirements of standard written English; that is, pay attention to grammar, choice of words, and sentence construction. Choose the answer that produces the most effective sentence; this answer should be clear and exact, without awkwardness, ambiguity, redundancy, or grammatical error.

The gap in the ozone layer over the North Pole can expand each summer enough that it exposes regions as far south as Sweden by heightened UV radiation, also increasing rates of skin cancer in the northern regions by as much as 50 percent.（）
A. that it exposes regions as far south as Sweden by heightened UV radiation, also increasing
B. that regions as far south as Sweden have been exposed to heightened UV radiation, as well as having increased
C. to expose regions as far south as Sweden to heightened UV radiation, increased
D. to expose regions as far south as Sweden to heightened UV radiation and increase
E. that exposure to heightened UV radiation in regions as far south as Sweden, as well as increasing

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[单项选择]When the Americans were getting ready to (41) their first men to the moon, an old Irishman was watching them on TV in a restaurant.
There was an Englishman in the restaurant, (42) . And he said to the Irishman, "The Americans are very clever, (43) they They are going to send some men to the moon. It’s a very long way (44) our world."
"Oh, that’s (45) . "The Irishman answered very quickly. "The Irish are going to send some men to the sun (46) a few months’ time. That’s much (47) away than the moon."
The Englishman was very (48) when he heard this. "Oh, yes, it is," he said, "But the sun is (49) hot for people to go to. The Irishman laughed and answered, "Well, we are not stupid, you know. We (50) go to the sun during the day, of course, We’ll go there during the night./

A. nothing
B. all.
C. OK

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[单项选择]有如下程序：
#include＜iostream＞
using namespace std;
class A
public:
static int a;
void init（　）a=1;
A(int a=2)init（　）; a++;
;
int A::a=0;
A obj;
int main（　）

cout＜＜obj.a;
return 0;
运行时输出的结果是( )。
A. 0
B. 1
C. 2
D. 3

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[单项选择]有如下程序： #include＜iostream＞ using namespace std; class A public: static int a; void init（ ）a=1; A(int a=2)init（ ）; a++; ; int A::a=0; A obj; int main（ ） cout＜＜obj.a; return 0; 运行时输出的结果是( )。A. 0B. 1C. 2D. 3

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[单项选择]有如下程序：
#include＜iostream＞
using namespace std;
class A
public:
static int a;
void init（　）a=1;
A(int a=2)init（　）; a++;
;
int A::a=0;
A obj;
int main（　）

cout＜＜obj.a;
return 0;
运行时输出的结果是( )。
A. 0
B. 1
C. 2
D. 3